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This calculus video tutorial explains how to solve work problems.  It explains how to calculate the work required to lift an object against gravity or the work required to push a car with a constant force to a certain displacement.  This video also explains how to calculate the work done by a variable using calculus.  The definite integral of a force function with respect to x is equal to the work done.

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This calculus video tutorial explains how to solve work problems. It explains how to calculate the work required to lift an object against gravity or the work required to push a car with a constant force to a certain displacement. This video also explains how to calculate the work done by a variable using calculus. The definite integral of a force function with respect to x is equal to the work done. This lesson explains how to calculate the work required to pull a rope to the top of the building as well as the work done in pulling half of the rope to the top of the building. In addition, it explains how to calculate the work required to stretch a spring beyond its natural length using hooke's law and by calculating the value of the spring constant. Finally, this tutorial contains an example problem that explains how to calculate the work required to pump all of the water inside an inverted conical tank to the top of the tank. You need to know the density of water and the gravity acceleration for that problem. This video contains plenty of examples and practice problems. Calculus Video Playlist: https://www.youtube.com/watch?v=1xATmTI-YY8&t=25s&list=PL0o_zxa4K1BWYThyV4T2Allw6zY0jEumv&index=1 Access to Premium Videos: https://www.patreon.com/MathScienceTutor https://www.facebook.com/MathScienceTutoring/

Comments

Anonymous

Hey, I'm having trouble with a lightbulb problem? I have the concept do to it must be S.A. of a sphere + SA of a cylinder would be greater than the S.A. of a light bulb as the sphere part is cut at the bottom to fit exactly on the cylinder. To me, that means that the cylinder is a straight-forward S.A. and the sphere is needs to be subtracted a bit to find the exact S.A.